Using a chi-square goodness –of-fit test you can decide, with some degree of certainty, whether a variable is normally distributed. In all chi-square tests for normality, the null and alternative hypotheses are as follows. Ho: The test scores have a normal distribution. Ha: The test scores do not have a normal distribution. Find the expected frequencies. Round to the nearest integer as needed. Class boundaries 49.5 – 58.5 58.5 – 67.5 67.5 – 76.5 76.5 – 85.5 85.5 – 94.5 Frequency, f 18 61 83 33 5 Expected frequency Determine the Critical value, Xo2 = Calculate the test statistic X2 =
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Using a chi-square goodness –of-fit test you can decide, with some
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